I ve been thinking about you oh na na na

#I ve been thinking about you oh na na na how to#
#I ve been thinking about you oh na na na mac#

I've been thinking about some usage of sum(!is.na(unique(ID))), but I'm not sure how to conditionally count the unique values without creating criteria in the i section of the data.table (Conflict = 1).

This is what the answer should be: testDT Look at this huge big pillow Come and lay your mind And walk inside my crooked thought And see what fun you'll find, oh Hell we can get dreamy, yeah Delicious, we can be happy, yeah So happy I've been thinking about you, yeah (and if you wanna come) And if you wanna come in You've got to knock three times You are entering the White Room That's.

I need to count the unique number of non-NA IDs that have a conflict flag of 1 and apply that count in a new column to each Name-Division grouping. KEVIN IOLE: I think you were asked this in a post-fight press conference, but Ill repeat it, because a lot of people didnt have a chance to see it. I've created a dummy variable to tell me if there is a conflict for each row of the data.table: testDT <- data.table(Name = c(rep('A',6),rep('B',5)), Do you think about me still Do ya Do ya Cause I've been thinking 'bout forever. But I think the dust needs to settle a little bit and we just need to just bask in this moment of, you know, me finally completing something that Ive been looking forward to for many years.

#I ve been thinking about you oh na na na mac#

I feel like there has to be an easy way to do this in data.table, but can't seem to figure it out. Struggling with Oh Na Na Become a better singer in 30 days with these videos Here we go ItвЂ™s time If it ainвЂ™t KK what you smoking on If it ainвЂ™t RosГ© tell вЂem carry on It ainвЂ™t вЂbout mine вЂless the money long Oh na na na na na na Oh na na na na na na Oh na na na na na na Oh na na na na na na Oh na na na na na na Fat sack in hand Mac and Dev Back in dreads Stacking bread Kush. I would like to count the number of conflicts in my dataset by group.